1) It increases at (-2,0)U(0,2) because durint those intervals it only output positive numbers basically f'(x)>0. It decreases at (-00, -2)U(2, 00) because f'(x)<0
2)at (0, 0) Right? Because an extrema is when F'(x) is zero or undefined
3)Concave up:(-00,-1.5)U(1.5, 00)
Concave down: (-1.5, 1.5)
concave up wher the slope is positive and concave down wher it is negative
4)it is probably x^5 cause it changes direction a couple of times also because the f'(x) looks like x^4.
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1. excellent!
ReplyDelete2. =( no. first off, at x=0, you don't know if the output f(x) is 0. second of all, there is no min or max at x=0 because the slope of f(x) does not change signs.
3. slope of f'(x), yes. =)
4. yup!